\int e^{2 x+3} \sin 6 x {\d} x= [AP EAPCET 18 May 2024 Shift 1]

Correct Answer is : e2x+320(sin6x−3cos6x)+c

\frac{e^{2 x+3}}{40}(2 \sin 6 x+6 \cos 6 x)+c

\frac{e^{2 x+3}}{40}(2 \cos 6 x+6 \sin 6 x)+c

\frac{e^{2 x+3}}{20}( \sin 6 x-3 \cos 6 x)+c

\frac{e^{2 x+3}}{20}(\cos 6 x-3 \sin 6 x)+c

Indefinite Integration

Section: Mathematics

Question : 85 of 89

Marks: +1, -0

∫e2x+3sin‌6xdx=

[AP EAPCET 18 May 2024 Shift 1]

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