Limits Continuity and Differentiability

Section: Mathematics

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Question : 47 of 61

Marks: +1, -0

lim

x⟶‌

π

4

‌

4√2−(cos‌x+sin‌x)5

1−sin‌2x

=

[AP EAPCET 20 May 2024 Shift 2]

‌5√2
‌3√2
‌2√2
‌√2

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