x⊗y=2x+3y+4,x⊙y=xy+3\Rightarrow(2⊗3)⊙(3⊗4)=

AP ICET 2017 Shift 2 Paper

Question : 74 of 200

Marks: +1, -0

x⊗y=2x+3y+4,x⊙y=xy+3⇒(2⊗3)⊙(3⊗4)=

Solution:

Given :

x⊗y=2x+3y+4

and

xy=xy+3

∴2⊗3=2×2+3×3+4=17

3⊗4=2×3+3×4+4=22

Now,

(2⊗3)(3⊗4)=17⊚22=17×22+3=37

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