The middle term in the expansion of (x^2-1/{2x})^{10} is

AP ICET 2019 Shift 1 Paper

Question : 130 of 200

Marks: +1, -0

The middle term in the expansion of

(x^2-1/{2x})^{10}

Solution:

Middle term is

t_{n/2}+1=t_6

t _{6}=10 c _{5}( x ^{2})^{10-5}(\;{-1}/{2 x })^{5}

=\;{-63}/{8} x ^{5}

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