AP ICET 2019 Shift 1 Paper

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Question : 132 of 200

Marks: +1, -0

If A =

[\table 3,-4;1,-1]

, then

A^4-A^3+A^2-A

=

$[\table 4,-8;2,-4]$
$[\table 5,-8;2,-3]$
$[\table 7,-12;3,5]$
$[\table 4,-6;1,-3]$

Solution:

A(\table3,-4;1,-1),A^2=(\table5,-8;2,-3)

=A^{4}-A^{3}+A^{2}=A

=(A^{2}+I)(A^{2}-A)

=(\table6,-8;2,-2)(\table2,-4;1,-2)=(\table4,-8;2,-4)

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