AP ICET 2019 Shift 1 Paper

Question : 137 of 200

Marks: +1, -0

A and B are the end points of the longest line drawn in the circle with centre If C is a point on the circle such that AC = Ax = 3. Then the perimeter of Δ ABC is

${9√3}/2$
9
6 + $3√3$
9 + $3√3$

Validate

Solution:

IN the circle X is the Centre
∴ AX = AC = 3 (radii of the same circle)
AB = 6 cm
∠C = 90°⇒ ΔABC is right triangle

∴AB^2=AC^2+BC^2

6^2+3^2+BC^2

⇒BC=√27=3√3

∴ Perimeter of ΔABC is AB + BC + AC

=6+3 √{3}+3=9+3 √{3}

Go to Question:

Prev Question

Next Question