AP ICET 2019 Shift 1 Paper

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Question : 88 of 200

Marks: +1, -0

The increasing order of a =

√7-√6

, b =

√3-√2

, c =

√6-√5

, d =

√2-1

is

c,a,b,d
a,c,b,d
a,c,d,b
a,d,c,b

Solution:

Given,

a =√7-√6=1/{√7+√6}

b =√{3}-√{2}=\;{1}/{√{3}+√{2}}

C =√{6}-√{5}=\;{1}/{√{6}+√{5}}

d =√{2}-1=\;{1}/{√{2}+1}

(√{7}+√{6})>(√{6}+√{5})>(√{3}+√{2})>(√{2}+1)

∴ The ascending order = a < c < b < d.

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