AP ICET 2019 Shift 2 Paper

Question : 80 of 200

Marks: +1, -0

If x = 4 -

∛7

, then

x^3-12x^2+48x-21

Solution:

Given

x=4-√[3]{7}

⇒ x-4=-√[3]{7}

Cubing on both sides

⇒(x-4)^{3}=-7

⇒ x^{3}-12 x^{2}+48 x-64=-7

⇒ x^{3}-12 x^{2}+48 x-21=43-7=36

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