10 + 4\:of\:3 \div [\:8 \times 3\: \\stackrel{¯}{\:12 \div 6\: (25−12 \times 3 + \:8−4 \times {3}\:) \} ] = \:

AP Police Constable Prelims 6-Jan-2019 Paper

Question : 47 of 200

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10 + 4\:of\:3 ÷ [\:8 × 3\: \{\:12 ÷ 6\: (25−12 × 3 + \:8−4 × \;{3}↖{¯}\:) \} ] = \:

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