BITSAT 2011 Paper

Since 3(1) + 2(– 2) + (–1) (–1) = 3 – 4 + 1 = 0
∴ Given line is ⊥ to the normal to the plane i.e.,
given line is parallel to the given plane.
Also, (1, –1, 3) lies on the plane x – 2y – z = 0 if
1 – 2 (–1) – 3 = 0 i.e., 1 + 2 – 3 = 0
which is true
∴ L lies in plane π.