If f (x) = \\begin{array}{c}{x^2+3x-10\end\frac{array}{x^2+2x-15} , \when x \neq -5;a , \when x = -5 is continuous at x = –5, then the value of ‘a’ will be

BITSAT 2013 Paper

Section: Mathematics

Question : 109 of 150

Marks: +1, -0

If f (x) =

{

x2+3x−10

x2+2x−15

when‌x≠−5

when‌x=−5

is continuous at x = –5, then the value of ‘a’ will be

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