Consider x/2+y/4 ≥ 1 and x/3+y/2 ≤ 1 ,x, y ≥ 0. Then number of possible solutions are :

BITSAT 2019 Paper

Section: Mathematics

Question : 91 of 150

Marks: +1, -0

Consider

≥ 1 and

≤ 1 ,x, y ≥ 0.
Then number of possible solutions are :

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