Electrode potential data are given below: {\Fe}^{+3}( {\aq})+ {\e}^{-} \to {\Fe}^{+2}( {\aq}) ; {\E}^{\circ}=+0.77 {\V} {\Al}^{3+}( {\aq})+3 {\e}^{-} \to {\Al}_{( { s})} ; {\E}^{\circ}=-1.66 {\V} {\Br}_2( {\aq})+2 {\e}^{-} \to 2 {\Br}^{-}( {\aq}) ; {\E}^{\circ}=+1.08 {\V} Based on the data, the reducing power of {\Fe}^{2+}, {\Al} and {\Br}^{-}will increase in the order

Correct Answer is : Br−<Fe2+<Al

BITSAT 2023 Shift 1 Paper

Section: Chemistry

Question : 60 of 130

Marks: +1, -0

Electrode potential data are given below:
‌Fe+3(aq)+e−→Fe+2(aq);E∘=+0.77V
‌Al3+(aq)+3e−→Al( s);E∘=−1.66V
‌Br2(aq)+2e−→2Br−(aq);E∘=+1.08V
Based on the data, the reducing power of Fe2+, Al and Br−will increase in the order

Br−<Fe2+<Al
Fe2+<Al<Br−
Al<Br−<Fe2+
Al<Fe2+<Br

Validate

	Fe	Al	Br
E‌Red ‌∘	0.77	−1.66	1.08
EOxi∘	−0.77	1.66	−1.08

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