BITSAT 2024 Shift 1 Paper

In Young's double slit experiment within a medium with a refractive index of 1.33 , the maximum intensity is represented as I0.
To find the intensity at a point on the screen where the path difference between the light from the slits is ‌

λ

4

, follow these steps:
Path Difference: Given as ∆x=‌

λ

4

.
Phase Difference Calculation:
φ=(‌

2π

λ

)×∆x
Substituting the given path difference:
φ=‌

2π

λ

×‌

λ

4

=‌

π

2

Intensity Calculation: The intensity at any point on the screen with a phase difference φ is given by:
I=I0cos2(‌

φ

2

)
Substituting the phase difference:
I=I0cos2(‌

π∕2

2

)
Simplifying further:
I=I0cos2(‌

π

4

)
I=I0(‌

1

√2

)2
I=‌

I0

2

Thus, the intensity at the specified point on the screen is ‌

I0

2

.