BITSAT 2024 Shift 1 Paper

v=√2×g×h=√2×9.8×4.9=9.8m∕ s
where:
g=9.8m∕ s2 (acceleration due to gravity)
h=4.9m‌ (height) ‌
Next, calculate the velocity after the first bounce using the coefficient of restitution e=‌

3

4

:
v‌bounce ‌=e×9.8=‌

3

4

×9.8=7.35m∕ s
The time taken for the ball to travel up and back down after the first bounce, until it hits the surface again, is:
‌t=‌

2v‌bounce ‌

g

=‌

2×7.35

9.8

‌t=‌

14.7

9.8

=1.5 s
Therefore, the ball will hit the surface for the second time after 1.5 seconds.