Consider the function f(x)=\frac{|x-1|}{x^2}, then f(x) is

Correct Answer is : decreasing in (0,1)∪(2,∞)

increasing in (0,1) \cup(2, \infty)

increasing in (-\infty, 0) \cup(0,1)

decreasing in (-\infty, 0) \cup(2, \infty)

decreasing in (0,1) \cup(2, \infty)

BITSAT 2024 Shift 1 Paper

Question : 80 of 130

Marks: +1, -0

Consider the function f(x)=‌

|x−1|

, then f(x) is

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