BITSAT 2024 Shift 1 Paper

To solve the problem, we need to arrange the digits of the number 223355888 so that the odd digits occupy even positions. We have:
Odd digits: 3,3,5,5
Even digits: 2,2,8,8,8
The number positions can be represented as:
OEOEOEOEO
Where E indicates even positions and O indicates odd positions.
Steps:
Arranging Odd Digits on Even Positions:
There are 4 even positions available for the odd digits (3,3,5,5). The number of ways to arrange these with repetitions is given by:
‌

4!

2!2!

Arranging Even Digits on Odd Positions:
There are 5 odd positions available for the even digits (2,2,8,8,8). The number of ways to arrange these with repetitions is given by:
‌

5!

2!3!

Calculating Total Arrangements:
By multiplying the number of ways to arrange the odd and even digits, we get the total number of 9-digit numbers that can be formed:
‌

4!

2!2!

×‌

5!

2!3!

=60
Thus, there are 60 different ways to arrange the digits to meet the given conditions.