BPSC 44th Exam Prelims 2002 Solved Paper

Question : 118 of 150

Marks: +1, -0

For data (1, 6) (2, 9), (3, 6), (4, 7), (5, 8), (6, 5), (7, 12), (8, 3), (9, 17), (10, 1) covariance is –

Solution:

\ov{x} \;\; =\;{1+2+3+4+5+6+7+8+9+10}/{10}

\;\; =5.5

\ov{y}=\;{6+9+6+7+8+5+12+3+17+1}/{10}

\ov{y}=7.4

Covariance

=\;{Σ(x_{i} y_{i}-\ov{x} \ov{y})}/{n}

\;\; =\;{411-407}/{10}=\;{4}/{10}

= \;\; 0.4

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