BPSC 44th Exam Prelims 2002 Solved Paper

Question : 121 of 150

Marks: +1, -0

Find the value of 13°12' from the following –

Solution:

13^{∘} 12^{'}

=13^{∘}+(\;{12}/{60})^{∘} \;\; \;\; [ ∵ 1^{∘}=60^{'}]

=13^{∘}+(\;{1}/{5})^{∘}=(\;{66}/{5})^{∘}

=\;{66}/{5} × \;{π}/{180}

[ ∵ π radians

=180^{∘}]

=\;{11 π}/{150}

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