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BSc Nursing GNM 2019 Solved Paper
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© examsiri.com
Question :
65 of 200
Marks:
+1
,
-0
Solubility of AgCl will be minimum in
0.01
M
N
a
C
l
solution
0.01
M
C
a
C
l
2
solution
pure water
0.001
M
A
g
N
O
3
solution
Validate
Solution:
N
a
C
l
⇌
N
a
+
+
C
l
−
C
a
C
l
2
⇌
C
a
2
+
+
2
C
l
−
H
2
O
⇌
H
+
+
O
H
−
A
g
N
O
3
⇌
A
g
+
+
N
O
3
−
C
a
C
l
2
in solution is dissociated into 3 ions (maximum).Due to common ions effect solubility of
A
g
C
l
will be minimum in
0.01
M
C
a
C
l
2
solution.
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