EMF of a cell whose half cells are given below is{Mg}^{2+}+2 e^{-} \rightarrow {Mg}(s) ; E=-2.37 {V} {Cu}^{2+}+2 e^{-} \rightarrow {Cu}(s) ; E=+0.33 {V}

BSc Nursing GNM 2019 Solved Paper

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EMF of a cell whose half cells are given below isMg2++2e−⟶Mg(s);E=−2.37V
Cu2++2e−⟶Cu(s);E=+0.33V

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