CAT 2020 Exam Shift 3 Solved Paper

The line $\mathit{y}=|\mathit{x}-2|+4$ intersects the $\mathit{y}$ -axis at $\left(0,6\right)$ and intersects $\mathit{x}=2$ at $\left(2,4\right)$
The other vertices are $\left(0,0\right)$ and $\left(2,0\right)$
The figure formed is a trapezium of parallel sides 6 and 4 and the distance between the parallel sides is 2 .
Required answer $=\frac{1}{2}\times 2\times \left(6+4\right)=10$