CAT 2023 Slot 2 Solved Paper

From the inequality and nature of $\mathit{x}$, and $\mathit{y}$, we get the given diagram:We need to find the area of the quadrilateral $\mathit{A}\mathit{B}\mathit{D}\mathit{E}=$ area of rectangle $\mathit{A}\mathit{B}\mathit{C}\mathit{D}+$ area of triangle $\mathit{C}\mathit{D}\mathit{E}$ $\Rightarrow$ Area of $\mathrm{ABCD}=\left(7-3\right)\star 5=20$ units, and the area of triangle $\mathrm{CDE}=\left(\frac{1}{2}\right)\star 10\star 5=25$ units. Hence, the area of the quadrilateral $\mathit{A}\mathit{B}\mathit{D}\mathit{E}=\left(20+25\right)=45$ units.