CDS Model Paper 5 Mathematics

Sum of the three exterior angles
=(∠1+∠2)+(∠2+∠3)+(∠3+∠1)
=2(∠1+∠2+∠3) (Sum of the interior angles are 180°)
=2×180°=360°
Sum of exterior angles of any polygon =360°
Alternate Method
Sum of the Exterior angles
=(180°−∠A)+(180°−∠B)+(180°−∠C)
=540°−(∠A+∠B+∠C)
=540°−180° Sum of angles of a triangle is 180°)
=360°