CDS Model Paper 5 Mathematics

AB=15
BC=25
AC=x, then
We know that the sum of two sides of a triangle is always greater than third side.
⇒ AB+BC>x
⇒ 15+25>x
⇒ 40>x ...(i)
Also, the differences of two sides is always less than third side.
BC−AB<AC
25−15<x
10<x ...(ii)
From eq. (i) and (ii)
10<x<40