CG TET 2019 Math and Science Solved Paper

Question : 126 of 150

Marks: +1, -0

\;{(2019−1)(2019\;+\;1)(2018−1)(2018\;+\;1).....(2−1)(2\;+\;1)}/{(2019^{2}−1)(2018^{2}−1).....(2^{2}−1)} =

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