CGPET 2012 Solved Paper

Given curves are y=|x−1| and y=3−|x|.
The intersection point of lines x+y=1 and y−x=3 is B(−1,2).
and intersection point of lines x−y=1 and y=3−x is D(2,1)Now, Area of
△ACE=‌

1

2

×AE×OC=‌

1

2

×6×3=9
Area of △ABF=‌

1

2

×AF×BG=‌

1

2

×4×2=4
and
Area of △FDE=‌

1

2

×EF×DH=‌

1

2

×2×1=1
∴ Required shaded region
= Area of △ACE - Area of △ABF
- Area of △FDE
=9−4−1=4 sq units