CGPET 2012 Solved Paper

Section: Mathematics

© examsiri.com

Question : 144 of 150

Marks: +1, -0

The value of 2,6,10...(4n−6)(4n−2) is equal to

C(2n,n)
(n+1)(n+2)(n+3)...(2n)
n!P(2n,n)
None of above

Go to Question:

Prev Question

Next Question