CGPET 2017 Solved Paper

Given
Empirical formula =CH2O
Mole-ratio of C, H and O=1:2:1
Also 0.0833 moles contains 1g of hydrogen
∴0.0833×n=1g of hydrogen
where n= number of moles of hydrogen
(a) For C5H10O5(n=10)
∴0.0833×10=0.833≠1
(b) For C3H4O3(n=4)
∴0.0833×4=0.333≠1
(c) For C12H22O11(n=22)
∴0.0833×22=1.8326≠1
(d) For C6H12O6(n=12)
∴0.0833×12=0.9996≈1=1