COMEDK 2023 Shift 1 Paper

The impedance of an inductor (ZL) is given by the formula:
ZL=2πfL
where:
f is the frequency of the AC source in Hertz(Hz),
L is the inductance in Henrys (H),
2πf represents the angular frequency of the AC source.
In this case, we are dealing with a maximum current (Imax) of √2A and a voltage source of 200V operating at 50‌Hz. The relationship between the voltage (V), impedance (ZL), and maximum current (Imax) can be expressed as:
V=Imax⋅ZL
We can rearrange this formula to solve for L :
L=‌

V

Imax⋅2πf

Substituting the given values:
L=‌

200

√2⋅2π⋅50

After simplification:
‌L=‌

200

√2⋅314.16

‌L=‌

200

222.53

Further simplification gives:
L=‌

2

√2π

Simplifying the √2 in the denominator by multiplying numerator and denominator by √2 gives:
‌L=‌

2√2

π√2

‌L=‌

2

π

H
Hence, the correct answer is Option C: ‌

2

π

H.