The binding energy of a nucleus is the energy required to disassemble the nucleus into its constituent protons and neutrons. The formula to calculate the binding energy is given by: Binding Energy =( Total mass of individual nucleons - Mass of the nucleus )×931.5‌MeV, For tritium (‌13H), it consists of 1 proton and 2 neutrons. We are given the following masses: For tritium (‌13H), it consists of 1 proton and 2 neutrons. We are given the following masses: Mass of tritium nucleus, m⊤=3.01605u Mass of a proton, mp=1.00782u Mass of a neutron, mn=1.00866u First, we calculate the total mass of individual nucleons: Total mass of nucleons =1×1.00782u+2×1.00866u ‌=1.00782u+2.01732u ‌=3.02514u Next, we calculate the mass defect (difference between the total mass of individual nucleons and the mass of the nucleus): Mass defect = Total mass of nucleons - Mass of the nucleus ‌=3.02514u−3.01605u ‌=0.00909u Now, we convert the mass defect into energy using the conversion factor 931.5‌MeV∕u : Binding Energy =0.00909u×931.5‌MeV∕u ≈8.5‌MeV Therefore, the binding energy of the tritium nucleus is approximately 8.5 MeV . Hence, the correct option is: Option A: 8.5 MeV