A given chemical reaction is represented by the following stoichiometric equation. 3 X+2 Y+\frac{5}{2} Z \rightarrow P_1+P_2+P_3 The rate of reaction can be expressed as

Correct Answer is : 23(d[X]dt)=(d[Y]dt)=45(d[Z]dt)

\frac{2}{3} (\frac{d[X]}{d t}) = (\frac{d[Y]}{d t}) =\frac{4}{5} (\frac{d[Z]}{d t})

\frac{3}{2} (\frac{d[X]}{d t}) =\frac{1}{4} (\frac{d[Y]}{d t}) =\frac{8}{5} (\frac{d[Z]}{d t})

\frac{4}{15} (\frac{d[X]}{d t}) =\frac{4}{5} (\frac{d[Y]}{d t}) =\frac{8}{15} (\frac{d[Z]}{d t})

(\frac{d[X]}{d t}) =\frac{3}{2} (\frac{d[Y]}{d t}) =\frac{15}{4} (\frac{d[Z]}{d t})

COMEDK 2024 Shift 1 Paper

Question : 52 of 180

Marks: +1, -0

A given chemical reaction is represented by the following stoichiometric equation.
3X+2Y+‌

Z⟶P1+P2+P3
The rate of reaction can be expressed as ‌‌‌‌

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