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Question : 130 of 180
Marks:
+1,
-0
Solution:
‌‌| sin‌x−sin‌3x |
| sin‌2x−cos2x |
‌=‌| 2sin‌()‌cos() |
| −(cos2x−sin‌2x) |
‌=‌| 2‌cos‌2‌x‌s‌i‌n‌(−x) |
| −cos‌2‌x |
=‌| −2sin‌x‌cos‌2‌x |
| −cos‌2‌x |
=2sin‌x
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