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Question : 153 of 180
Marks:
+1,
-0
Solution:
Let
‌‌I=(x27‌cos‌x+ex)‌dx⇒‌‌I=x27‌cos‌x‌dx+ex‌dxSince,
f(x)=x27‌cos‌x is an odd function.
{∵f(x)‌dx=0‌ if ‌f(x)‌ is odd function ‌}So,
‌‌I=0+[ex]−11=e−‌
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