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Question : 162 of 180
Marks:
+1,
-0
Solution:
‌‌ We have, ‌‌log‌x‌dx‌‌=[log‌x‌∫1‌dx]1e−(‌‌log‌x‌∫1‌dx)‌dx‌‌=[log‌x⋅x]1e−‌⋅x‌dx‌‌=[e‌log‌e−1‌log(1)]−1‌dx‌‌=e−[x]1e=e−[e−1]=1
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