COMEDK Exam 2018 Solved Paper

If the line is inclined at angle 45∘ with the positive direction of the X-axis i.e. the points are situated at angle θ=45∘ from X-axis at a distance r=3√2 from point (4,−5)
The two points can be given by
(x0±r‌cos‌θ,y±rsin‌θ)
The points are
‌(4+3√2‌cos‌45∘,−5+3√2sin‌45∘)
‌‌‌‌‌=(4+3√2‌

1

√2

,−5+3√2×‌

1

√2

)=(7,−2)
‌‌ and ‌(4−3√2‌cos‌45∘,−5−3√2sin‌45∘)
‌‌=(4−3√2×‌

1

√2

,−5−3√2×‌

1

√2

)=(1,−8)
Thus, the points are (1,−8) and (7,−2).