COMEDK Exam 2021 Solved Paper

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Question : 145 of 180

Marks: +1, -0

∫‌

2x

√1−4x

‌dx is equal to

(log‌2)sin‌−12x+C
‌
1
2
sin‌−12x+C
‌
1
log‌2
sin‌−12x+C
2‌log‌2‌s‌i‌n‌−12x+C

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