COMEDK Exam 2022 Solved Paper

Let, the rate of diffusion of gas X,r1=b. Therefore, rate of diffusion of methane, r2=2b
According to Graham's law of diffusion,
(

r1

r2

)=(√

M2

M1

)
M1= molecular mass of gas X
M2= molecular mass of methane =16g
∴

b

2b

=√

16

M2

⇒ (

1

4

)=

16

M2

⇒ M2=64g
Therefore, molecular mass of X is 64g.