S \equiv x^2+y^2+2 x+3 y+1=0 \text{ and } {\S}^{'} \equiv x^2+y^2+4 x+3 y+2=0 are two circles. The point (-3,-2) lies

Correct Answer is : inside S′ only

COMEDK Exam 2022 Solved Paper

Question : 130 of 180

Marks: +1, -0

S≡x2+y2+2x+3y+1=0‌ and ‌
S′≡x2+y2+4x+3y+2=0 are two circles.
The point (−3,−2) lies

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