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COMEDK Exam 2022 Solved Paper
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© examsiri.com
Question :
137 of 180
Marks:
+1
,
-0
If
θ
be the angle between the vectors
a
=
2
^
i
+
2
^
j
−
^
k
and
b
=
6
^
i
−
3
^
j
+
2
^
k
, then
cos
‌
θ
=
‌
4
21
cos
‌
θ
=
‌
3
19
cos
‌
θ
=
‌
2
19
cos
‌
θ
=
‌
5
21
Validate
Solution:
c
o
s
θ
=
a
.
b
|
a
|
|
b
|
=
(
2
^
i
+
2
^
j
−
^
k
)
.
(
6
^
i
−
3
^
j
+
2
^
k
)
√
2
2
+
2
2
+
(
−
3
)
2
√
6
2
+
(
−
3
)
2
+
2
2
=
12
−
6
−
2
√
4
+
4
+
1
√
36
+
9
+
4
=
4
21
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