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Question : 144 of 180
Marks:
+1,
-0
Solution:
Here
f(x)=cosx f(-x) = cos(-x)=cos x=f(x)
So,
f is even function.
∴
∫−cosxdx=2‌∫0cosxdx [∵∫−aaf(x)dx=2‌∫0af(x)dx,if‌f‌is‌even] =2[sinx]0 =2[sin−sin0]=2[1−0]=2
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