COMEDK Exam 2022 Solved Paper

Radius of the circular disc =R
Suppose, centre of mass of remaining portion is at a distance C2 from the C.
Now, A1(CC1)=A2(CC2)
For square, (side)2+(side)2=(radius)2
2(side)2=R2
(side)2=

R2

2

side=

R

√2

Now, A1(CC1)=A2(CC2)
∴ CC2=

A1

A2

(CC1)
A1= area of the square =(

R

√2

)2
A2= area of the remaining part of the circe
=πR2−(

R

√2

)2
CC2=

( R √2 )2

πR2−( R2 √2 )2

.(

R

2

)
=

R2

2πR2−R2

.

R

2

=

R.R.R

R2(2π−1)2

=

R

4π−2