CTET 2 Math and Science 2011 Paper

Question : 44 of 120

Marks: +1, -0

The factorisation of

25-{p}^2-{q}^2-2{pq}

Solution:

Consider

25-{p}^{2}-{q}^{2}-2{pq}

=-[p^{2}+q^{2}+2pq-25]

=-[(p+q)^{2}-(5)^{2}]

∵((a+b)^{2}=a^{2}+b^{2}+2ab)

=-[(p+q+5)(p+q-5)]

(∵(a^{2}-b^{2})=(a+b)(a-b)).

=(p+q+5)(5-p-q)

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