CTET 2 Math and Science Dec 2019 Paper

Question : 44 of 120

Marks: +1, -0

If 5(3x + 4) – 8(6x + 7) = 9x – 8, then what is the value of (

x^2

– 2x + 1)?

Solution:

Given, 5(3x + 4) – 8(6x + 7) = 9x – 8
⇒ 15x + 20 – 48x – 56 = 9x – 8
⇒ –33x – 36 = 9x – 8
⇒ –33x – 9x = +36 – 8
⇒ - 42x = 28
⇒ x =

-2/3

∴x^2-2x+1

=(-2/3)^2-2×(-2/3)+1

=4/9+4/3+1=25/9

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