CTET 2 Math and Science Sep 2016 Paper

Let the angles of the quadrilateral be 2x, 3x, 5x and 8x.
Since, the sum of the angles of a quadrilateral is 360°
Then,
$2\mathit{x}+3\mathit{x}+5\mathit{x}+8\mathit{x}={360}^{\circ }$
$18\mathit{x}=360°$
$\mathit{x}=20°$
Then, the angles of quadrilateral are,
$2\mathit{x}=2\mathit{x}\times 20°=40°$
$3\mathit{x}=3\times 20°=60°$
$5\mathit{x}=5\times 20°=100°$
$8\mathit{x}=8\times 20°=160°$
Largest angle is 160° and smallest angle is 40°
Now the supplement angle of $160°=180°\mathit{–}160°=20°$
And complement angle of $40°=90°\mathit{–}40°=50°$.
Hence, the sum of supplement of largest angle and complement of smallest angle of quadrilateral is$=20°+50°=70°.$