\int \frac{d x}{x^2+4 x+5} is equal to

Correct Answer is : 12{tan−1(x+2)+x+2x2+4x+5}+c

\frac{1}{2} \{\tan ^{-1}(x+2)+\frac{x+2}{x^2+4 x+5}\} +c

\frac{1}{2} \{\tan ^{-1}(x+2)+\frac{x}{x^2+4 x+5}\} +c

\frac{1}{2} \{\tan ^{-1}(x+2)+\frac{x-2}{x^2+4 x+5}\} +c

\frac{1}{2} \{\tan ^{-1}(x-2)+\frac{x}{x^2+4 x+5}\} +c

CUSAT 2021 BTech Solved Paper Shift 3

Question : 238 of 250

Marks: +1, -0

∫‌

x2+4x+5

is equal to

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