CUSAT 2022 BTech Solved Paper Shift 4

© examsiri.com
Question : 182 of 200
 
Marks: +1, -0
For every real number t, let f(t)=‌
t
1!
+‌
3
2!
t2
+‌
7
3!
t3
+‌
15
4!
t4
+...
Then the equation f(t)=0 has
Go to Question: