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Question : 93 of 160
Marks:
+1,
-0
Solution:
Let
‌‌S=‌+‌+‌+‌+...∴‌‌Tn=‌‌=‌−‌⇒‌‌‌‌S=Tn=(‌−‌)=‌‌−‌+‌−‌+‌−‌+‌−‌+‌−...=‌1+‌−‌+‌−‌+...=‌1−(−‌+‌−‌+‌−...)=‌1−(−1+loge2)=2−loge2
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