Given, α,β are the roots of x2−2x+4=0 ‌∴‌‌α+β=2 . . . (i) ‌‌ and ‌‌‌αβ=4 . . . (ii) ‌‌ Now, ‌‌‌α−β=√(α+β)2−4αβ ‌=√4−4×4=√−12 ‌⇒‌‌α−β=2√3i . . . (iii) On solving Eqs. (i) and (ii), we get ‌α=‌