GATE Civil Engineering (CE) 2018 Shift 1 Solved Paper

Speed of aircraft, ${\mathit{u}}_{\mathit{i}}=200\mathit{k}\mathit{m}/\mathit{h}\mathit{r}$
$=\frac{200\times 1000}{3600}=55.56\mathit{m}/\mathit{s}$
Deceleration of aircraft on the runway
Aircraft takes 18 sec to exit the runway strip.
Speed of the aircraft at the exit of the runway
${\mathit{u}}_{\mathit{f}}={\mathit{u}}_{\mathit{i}}+\mathit{a}\mathit{t}$
$=55.56-1.697\times 18=25.014\mathit{m}/\mathit{s}$
After runway aircraft decelerate with
Total distance travelled by the aircraft from the location of exit on the runway
${\mathit{U}}^2={\mathit{u}}^2+2\mathit{a}\mathit{S}$
$0={25.014}^2-2\times 1\times \mathit{S}$
$\mathit{S}=312.8\mathit{m}$